Title

Exaplanation.

Syntax

$adddays(date,number)

where

date a date, or an expression that evaluates to a DATE data type
number a number, or an expression that evaluates to a number

Return

Number, representing a DATE value.

Comments

Use $adddays to perform arithmetic with date values. $Adddays calculates a date value by adding a number representing days to a date value. If number is negative, the effect is to subtract the days from the date.

The + (add) and - (subtract) operators can be used to achieve the same results.

If date or the result of the functional expression is an invalid date (e.g., 19930231), it is adjusted to produce a valid date (e.g., 19930228).

Example

If $Date has the value 19981225, then

$adddays($date,5)

Evaluates to 19981230.

$adddays($date,7)

Evaluates to 19990101.

$adddays($date,-5)

Evaluates to 19981220.

$adddays(19990201,30)

Evaluates to 19990303.